A/26 subnetmeans26 bits for the networkand6 bits for host addressing(32 - 26 = 6):
2⁶ = 64 total addresses per subnet
64 - 2 =62 usable host addresses per subnet
/24 to /26 increases subnet bits by 2, so:
2² =4 subnetsfrom one /24
But the question asks aboutusing /26, which means:
From /24 → each /26 block gives64 IPs
So you get4 subnets total
But the options must be interpreted carefully!
→Let's calculate again properly:
/26 = 64 addresses per subnet (2⁶)
Usable hosts per subnet = 64 - 2 = 62
Number of subnets in /24 when divided by /26 = 2^(26 - 24) = 4 subnets
So correct result is:
4 subnets, 62 hosts per subnet→Correct Answer: C
However,Option D says 8 subnets, 30 hosts per subnet, which actually matches a/27 mask, not /26.
Final Correct Answer:C
[Reference:, Nokia IP Fundamentals Guide – Chapter: “Subnetting and Address Calculations”, Subnet Math – RFC 950 principles, , ]
Submit