The study guide explicitly states that slabs are used by the kernel : “The kernel memory slabs are collections of objects with a common purpose. The kernel uses them to store information in memory.”
It also gives the exact calculation method: “Total slab size = available objects x object size” and explains that in the diagnose hardware sysinfo slab output, the columns are active objects , available objects , and object size
From the exhibit:
tcp_session 3 5 1500 ...
available objects = 5
object size = 1500
So:
Total slab size = 5 × 1500 = 7500
That matches option B .
Why the other options are wrong:
A : ip_session 10 10 1408 ... gives 10 × 1408 = 14080 , but slabs are associated with the kernel , not user space
C : ip6_session 5 0 1472 ... gives 0 × 1472 = 0 , not 1472
D : UDPv6 15 10 1408 ... gives 10 × 1408 = 14080 , but again slabs are associated with the kernel , not user space
So the verified answer is B .
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