To determine which prefixes contain 192.168.3.29 , calculate the address range represented by each subnet mask.

A /22 prefix uses subnet mask 255.255.252.0 , producing blocks of four in the third octet. Therefore, 192.168.0.0/22 covers 192.168.0.0 through 192.168.3.255 . The address 192.168.3.29 falls within this range, making A correct .

A /28 uses mask 255.255.255.240 , creating blocks of 16 addresses. 192.168.3.0/28 covers 192.168.3.0 through 192.168.3.15 . Since 192.168.3.29 is outside this interval, B is incorrect .

A /23 uses mask 255.255.254.0 , creating blocks of two in the third octet. 192.168.2.0/23 covers 192.168.2.0 through 192.168.3.255 , so 192.168.3.29 is included , making C correct .

Finally, a /21 uses eight-value blocks in the third octet. The prefix represented by 192.168.252.0/21 belongs to the 192.168.248.0–192.168.255.255 range and therefore cannot contain 192.168.3.29.

Study Guide Reference Topics: Networking Fundamentals — IPv4 addressing, subnet masks, CIDR notation, subnet boundaries, and prefix-range calculations.