The study guide states:
“The kernel memory slabs are collections of objects with a common purpose. The kernel uses them to store information in memory.”
It also gives the exact calculation rule:
“Total slab size = available objects x object size”
From the exhibit:
tcp_session 3 5 1500 ...
So:
available objects = 5
object size = 1500
Therefore:
Total slab size = 5 × 1500 = 7500 kB
That makes D correct, and it is associated with the kernel, not user space.
Why the other options are wrong:
A is wrong because sctp_session 0 0 1600 ... gives 0 × 1600 = 0, but slabs are associated with the kernel, not user space.
B is wrong because ip_session 1 3 1200 ... gives 3 × 1200 = 3600, but again slabs are kernel memory, not user space.
C is wrong because ip6_session 0 0 1300 ... gives 0 × 1300 = 0, not 1300.
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