ECCouncil Certified Ethical Hacker Exam (CEHv12) 312-50v12 Question # 128 Topic 13 Discussion

ECCouncil Certified Ethical Hacker Exam (CEHv12) 312-50v12 Question # 128 Topic 13 Discussion

312-50v12 Exam Topic 13 Question 128 Discussion:
Question #: 128
Topic #: 13

The network in ABC company is using the network address 192.168.1.64 with mask 255.255.255.192. In the network the servers are in the addresses 192.168.1.122, 192.168.1.123 and 192.168.1.124. An attacker is trying to find those servers but he cannot see them in his scanning. The command he is using is: nmap 192.168.1.64/28.

Why he cannot see the servers?


A.

He needs to add the command ““ip address”” just before the IP address


B.

He needs to change the address to 192.168.1.0 with the same mask


C.

He is scanning from 192.168.1.64 to 192.168.1.78 because of the mask /28 and the servers are not in that range


D.

The network must be dawn and the nmap command and IP address are ok


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