A = 192.168.10.0/26

B = 192.168.1.0/23

C = 10.0.0.1/18

Using the choices shown in the screenshot, the best-fit subnet selections are based on host growth requirements first, then segmentation .

For Company A , the current device count is 32 . With 20% growth , that becomes about 39 devices . A /27 only supports 30 usable hosts , so it is too small. A /26 supports 62 usable hosts , so 192.168.10.0/26 is the correct choice.

For Company B , the current device count is 100 . With 20% growth , that becomes 120 devices . The smallest correct subnet would normally be a /25 with 126 usable hosts , but that option is not shown. From the available choices, 192.168.1.0/23 is the smallest subnet that still supports more than 120 hosts, so that is the best answer.

For Company C , the current device count is 10,000 . With 20% growth , it needs space for 12,000 hosts . A /18 provides 16,382 usable hosts , while a /19 is not available and a /21 or /22 would be far too small. Therefore, 10.0.0.1/18 is the correct selection.

One important note: the dropdown choices shown do not actually let all three companies be placed into a single true Class B network block. So these answers are the best valid selections from the provided options .