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What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };

string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight"," ten"};

map m;

for(int i=0; i<10; i++) {

m.insert(pair(second[i],first[i]));

}

if (m[11] == "eleven") {

cout<<"eleven ";

}

for(map::iterator i=m.begin();i!= m.end(); i++) {

cout<second<<" ";

}

cout<

return 0;

}

What happens when you attempt to compile and run the following code? Choose all possible answers.

#include

using namespace std;

template

class A {

T_v;

public:

A() {}

A(T v): _v(v){}

friend ostream & operator<<(ostream & c, const A & v) {

c<

}

};

int main()

{

Aa(10);

cout<<a<

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

#include <algorithm>

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

string t[]={"aaa","Aaa", "aAa","aaA","bbb","Bbb", "bBb", "bbB"};

vector v1(t, t+8);

sort(v1.begin(), v1.end());

for_each(v1.begin(), v1.end(), Out(cout));cout<

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include <algorithm>

#include

#include

using namespace std;

void myfunction(int i) {

cout << " " << i;

}

int main() {

vector v1(10,1);

fill(v1.begin()+2, v1.end()?2,2);

fill_n(v1.begin()+4,2,3);

for_each(v1.begin(), v1.end(), myfunction);

return 0;

}

Program outputs:

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main(){

int myints[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };

vectorv(myints, myints+10);

set s1(v.begin(),v.end());

s1.insert(v.begin(),v.end());

s1.erase(s1.lower_bound(2),s1.upper_bound(7));

for(set::iterator i=s1.begin();i!= s1.end(); i++) {

cout<<*i<<" ";

}

return 0;

}

What will happen when you attempt to compile and run the following code? Choose all that apply.

#include

#include <algorithm>

#include

#include

using namespace std;

class A {

int a;

public:

A(int a) : a(a) {}

int getA() const { return a; } void setA(int a) { this?>a = a; }

bool operator < (const A & b) const { return a

};

class F {

A val;

public:

F(A & v):val(v){}

bool operator() (A & v) {

if (v.getA() == val.getA()) return true;

return false;

}

};

int main() {

int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };

vector v1(t, t + 10);

set s1(t, t + 10);

A a(6); F f(a);

find_if(s1.begin(), s1.end(), f);

if (find_if(v1.begin(), v1.end(), f) !=v1.end()) {

cout<<"Found!\n";

} else {

cout<<"Not found!\n";

}

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

class A {

public:

virtual int f() { return 10; }

virtual ~A(){}

};

class B: public A {

int f() {return 11; }

virtual ~B(){}

};

int main (){

std::vectorv1;

for(int i = 10; i>0; i??)

{

i%2>0?v1.push_back(new A()):v1.push_back(new B());

}

std::vector::iterator it = v1.begin();

while(it != v1.end())

{

std::cout<f()<<" ";

v1.pop_back();++it;

}

return 0;

}

What happens when you attempt to compile and run the following code?

#include

#include

using namespace std;

class A

{

int a,b;

public:

A & operator =(const A & c) { a = c.a; return *this;}

A():a(0),b(0){}

void setA(int a) {this?>a = a;} void setB(int b) {this?>b = b;}

int getA() {return a;} int getB() {return b;}

};

int main ()

{

vectorv;

A a;

a.setA(10); a.setB(11);

v.push_back(a);

A b = v.front(); v.pop_back();

cout<

return 0;

}