What happens if you try to compile and run this program?
#include
#include
int main (int argc, char *argv[]) {
int a = 0, b = 1, c;
c = a++ && b++;
printf("%d",b);
return 0;
}
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What happens if you try to compile and run this program?
#include
int fun(int i) {
return i++;
}
int main (void) {
int i = 1;
i = fun(i);
printf("%d",i);
return 0;
}
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What happens if you try to compile and run this program?
#include
int i = 0;
int main (int argc, char *argv[]) {
for(i; 1; i++);
printf("%d", i);
return 0;
}
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What happens if you try to compile and run this program?
#include
fun (void) {
static int n = 3;
return --n;
}
int main (int argc, char ** argv) {
printf("%d \n", fun() + fun());
return 0;
}
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What happens if you try to compile and run this program?
#include
int main (int argc, char *argv[]) {
int i = 1, j = 0;
int 1 = !i + !! j;
printf("%d", 1);
return 0;
}
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What happens if you try to compile and run this program?
#include
int main (int argc, char *argv[]) {
char *t = "abcdefgh";
char *p = t + 2;
int i;
p++;
p++;
printf("%d ", p[2] - p[-1]);
return 0;
}
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What happens if you try to compile and run this program?
#include
int main (int argc, char *argv[]) {
int i = 1;
for( ;; i/=2)
if(i)
break ;
printf("%d",i);
return 0;
}
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The program executes an infinite loop
What happens if you try to compile and run this program?
#include
int main(int argc, char *argv[]) {
int i = 2 / 1 + 4 / 2;
printf("%d",i);
return 0;
}
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What happens if you try to compile and run this program?
#include
#include
struct STR {
int i;
char c[20];
float f;
};
int main (int argc, char *argv[]) {
struct STR str = { 1, "Hello", 3 };
printf("%d", str.i + strlen(str.c));
return 0;
}
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What happens if you try to compile and run this program?
#include
int main (int argc, char *argv[]) {
char i = 20 + 020 + 0x20;
printf("%d",i);
return 0;
}
Choose the right answer:
