AP quantity
Correct deployment type
100,000 ft² / 9000 m² building 100,000/10,000 = 10 APs
Very low-density, low coverage
100,000 ft² / 9000 m² building 100,000/5000 = 20 APs
Coverage based design
100,000 ft² / 9000 m² building 100,000/2500 = 40 APs
Capacity based design with low to mid density
100,000 ft² / 9000 m² building 100,000/1500 = 67 APs
High-capacity design
Wireless access point density is determined by the coverage and capacity objectives of the proposed WLAN.
The calculations in the question represent preliminary planning estimates based on the total floor area and assumed service area per AP.
A very low-density deployment uses approximately one AP per 10,000 square feet, producing an initial estimate of ten APs for a 100,000-square-foot building.
A coverage-based deployment uses approximately one AP per 5,000 square feet, resulting in twenty APs.
For environments requiring additional client capacity, the design may use approximately one AP per 2,500 square feet, producing forty APs.
A high-capacity environment may require approximately one AP per 1,500 square feet, resulting in approximately sixty-seven APs.
Increasing access point density can improve spatial reuse and per-client capacity when channel planning, transmit power, and RF conditions are properly managed.
However, excessive AP density without appropriate RF engineering can increase co-channel interference and reduce network performance.
HPE Aruba Networking recommends validating AP placement through predictive design, application requirements, client-density analysis, and site surveys.
These figures are preliminary planning assumptions, not universal HPE deployment limits or guarantees of coverage.
Official HPE Reference: HPE Aruba Networking Campus Design Validated Solution Guide — RF Design, Capacity Planning and Access Point Placement.
Validated Solution Guide
The embedded exhibit contains a transcription error in its second calculation: 100,000 ÷ 500 is not 20. The correct divisor, as given in the question text, is 5,000.
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